In fig. de bc. then find ac

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WebAug 27, 2024 · Best answer The given figure: To find: area (ADE) : area (DECB) Given, DE BC, DE = 6 cm and BC = 12 cm In ∆ABC and ∆ADE, ∠ABC = ∠ADE [corresponding angle] ∠ACB = ∠AED [corresponding angle] And ∠A = ∠A [common side] ∴ ∆ABC ∼ ∆AED [by AAA similarity criterion] Then, WebHint: ab+ bc +ac = 2(a+b+c)2−(a2+b2+c2). The number of ordered triples (a,b,c) of positive integers which satisfy the simultaneous equations ab +bc = 44, ac +bc = 33. Your solution …

In fig., line BC line DE, AB = 2, BD = 3, AC = 4 and CE = x, then ...

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In the given figure, `DE BC and (AD)/(DB)=(3)/(5)`. If …

WebJan 8, 2024 · Find a quadratic polynomial whose zeroes are 5+ under root 2 and 5- under root 2. Convert it into rational number in form P/Q4.05 If x is a number whose simplest form is p/q , where p and q are integers and q not= 0,then x is a non- terminating repeating decimal only when q is no … WebFeb 22, 2024 · In the given figure,if DE BC,AE=8CM,EC=2CM AND BC=6CM,THEN FIND THE DE See answers Advertisement OmGupta11 As DE BC, and angle A is common, triangle … WebAnswer The diagonal BD of a parallelogram ABCD intersects the segment AE at the point F, where E is any point on the side BC. Prove that DF × EF = FB × FA. 1489 Views Answer ABC and DBC are two right triangles with common hypotenuse BC and with their sides AC and BD intersecting at point P. Prove AP × PC = DP × pb. 105 Views Answer ehrlich pest control fredericksburg va

RD Sharma Solutions for Class 10 Maths Chapter 4 Triangles Exercise 4.5

In Fig., DE AC and DC AP. Prove that BE/EC = BC/CP

WebBC = 2(5) + 2 = 10 + 2 = 12. AC = 3x = 3(5) = 15. DF = 6(5) = 30. EF = 3(5) + 9 = 15 + 9 = 24. Therefore, the length of the sides of the triangle are AB = 9 cm, BC = 12 cm, AC = 15 cm, DE = 18 cm, EF = 24 cm and DF = 30 cm. Try This: Let ABC and DEF be two triangles in which AB = DE, BC = FD and CA = EF. The two triangles are congruent under ... WebIn BPA, we haveDC ∥ AP [Given]∴ by basic prportionality theorem, we haveBC CP = BD DAIn BCA, we haveDE ∥ AC [Given]∴ by basic proportionality theorem, we haveBE BC = BD … ehrlich pest control hagerstownWebIn figure 1.13 BC⊥ AB, AD⊥ AB, BC = 4, AD = 8, then find A (ABC) /A ( ADB) . Solution: Here ABC and ADB have the same base AB. Areas of triangles with equal bases are proportional to their corresponding heights. Since bases are equal, areas are proportional to heights. Given BC = 4 and AD = 8 So, A (ABC) /A ( ADB) = BC/AD = 4/8 = 1/2 folk tales in pre spanish period

"WebApr 9, 2024 · A D A B = D E B C { ∴ A D E ∼ A B C } Now from figure, AD = 3 cm, DE = 2 cm and BD = 4 cm. So, AB = AD + BD = 3 + 4 = 7 cm. So, putting the value of AD, AB and DE we … " - In fig. de bc. then find ac

In fig. de bc. then find ac

In the given figure,if DE BC,AE=8CM,EC=2CM AND BC=6CM,THEN FIND THE DE …

WebJan 3, 2024 · In the given figure, `DE BC and (AD)/ (DB)= (3)/ (5)`. If `AC=4.8cm`, find the length of AE. Show more Show more License Creative Commons Attribution license (reuse allowed) In the given... Web(a) In the figure given below, AB DE, AC = 3 cm, CE = 7.5 cm and BD = 14 cm. Calculate CB and DC. Solution:- From the question it is given that, AB DE AC = 3 cm CE = 7.5 cm BD = 14 cm From the figure, ∠ACB = ∠DCE [because vertically opposite angles] ∠BAC = ∠CED [alternate angles] Then, ∆ABC ~ ∆CDE So, AC/CE = BC/CD 3/7.5 = BC/CD

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WebMar 29, 2024 · Transcript. Ex 6.2, 4 In figure, DE AC and DF AE. Prove that, prove that 𝐵𝐹/𝐹𝐸 = 𝐵𝐸/𝐸𝐶 Given: DE II AC and DF II AE To prove: 𝐵𝐹/𝐹𝐸=𝐵𝐸/𝐸𝐶 Proof: From (1) and (2) 𝐵𝐹/𝐹𝐸=𝐵𝐸/𝐸𝐶 Hence proved. Next: … WebThe diagonal BD of a parallelogram ABCD intersects the segment AE at the point F, where E is any point on the side BC. Prove that DF × EF = FB × FA. ABC and DBC are two right …

WebMar 16, 2024 · In Fig., if ∠A = ∠C, AB = 6 cm, BP = 15 cm, AP = 12 cm and CP = 4 cm, then find the lengths of PD and CD. asked Aug 27, 2024 in Triangles by Sima02 ( 49.6k points) … WebIn fig.4.140, ∠ABC = 90o and BD ⊥ AC. If AC = 5.7 cm, BD = 3.8 cm and CD = 5.4 cm, Find BC. Solution: Given: BD ⊥ AC AC = 5.7 cm, BD = 3.8 cm and CD = 5.4 cm ∠ABC = 90 o Required to find: BC We know that, ΔABC ∼ ΔBDC [By AA similarity] ∠BCA = ∠DCA = 90 o ∠AXY = ∠ABC [Common] Thus,

WebHint: ab+ bc +ac = 2(a+b+c)2−(a2+b2+c2). The number of ordered triples (a,b,c) of positive integers which satisfy the simultaneous equations ab +bc = 44, ac +bc = 33. Your solution is correct. Noe that a = 1,b −c = 11 and a = 11,b −c = 1 both lead to a+b = 12+ c. Then 33 = ac + bc = (12+ c)c indeed has no solution. WebMar 22, 2024 · Question 7 (Choice - 1) In the given fig. DE ∥ BC, ∠ADE = 70° and ∠BAC = 50°, then angle ∠BCA = ______Since DE ∥ BC ∠ ABC = ∠ ADE ∠ ABC = 70° By Angle sum property of triangle ∠ BAC + ∠ ABC + ∠ BCA = 180° 50° + 70° + ∠ BCA = 180° 120° + ∠ BCA = 180° ∠ BCA = 180° − 120° ∠ BCA = 60° 1/2 marks 1/2 marks Next: Question 7 (Choice - 2) → Ask …

WebApr 22, 2024 · Best answer We have, DE BC, AB = 6cm and AE = 1/4 AC In ΔADE and ΔABC ∠ADE = ∠ABC (corresponding angles) Then, ΔADE ~ ΔABC (By AA similarity) So,AD AB A …

WebFeb 18, 2024 · Find an answer to your question in the given figure, if DE BC, then find the length of AC . Pranitshende Pranitshende 19.02.2024 Math Secondary School answered … ehrlich pest control lewistown paWebMar 28, 2024 · Transcript. Ex 6.2, 6 In figure, A, B and C are points on OP, OQ and OR respectively such that AB PQ and AC PR. Show that BC QR. Given: AB II PQ and AC II PR To prove: BC II QR Proof: In ∆ 𝑂𝑃𝑄 AB II PQ (Line drawn parallel to one side of triangle, intersects the other two sides in distinct points, Then it divides the other 2 ... ehrlich pest control johnson city nyWebIn the given figure, DE BC and DE : BC = 3 : 5. Calculate the ratio of the areas of ∆ADE and the trapezium BCED - Mathematics ehrlich pest control lancaster paWebOct 23, 2024 · A Then (а) BD.CD = BC² (б) AB.AC = BC² (c) BD.CD = AD² (d) AB.AC = AD² Answer 11. D and E are respectively the points on the sides AB and AC of a triangle ABC such that AD = 2 cm, BD = 3 cm, BC = 7.5 cm and DE BC. Then, length of DE (in cm) is (a) 2.5 (b) 3 (c) 5 (d) 6 Answer 12. ehrlich pest control johnstownWebMar 27, 2024 · Complete step by step solution: In the given triangle ABC. We are given that AC = BC. This means that it is an isosceles triangle. And in an isosceles triangle the … ehrlich pest control live chatWebFeb 22, 2024 · In the given figure,if DE BC,AE=8CM,EC=2CM AND BC=6CM,THEN FIND THE DE See answers Advertisement OmGupta11 As DE BC, and angle A is common, triangle ADE ~ triangle ABC. AE = 8 cm, EC = 2 cm, AC = 8 + 2 = 10 cm As the both triangles are similar, Ratios of their respective sides are equal. AE / AC = DE / BC 8 / 10 = DE / 6 DE = 48 … folk tales of rajasthanWebOct 12, 2024 · To find: The value of EC. Solution: In the given figure, the triangles ABC and ADE have the ∠A common. Since BC and DE are parallel to one another, the angles ∠E and ∠C are equal. Also, angles ∠D and ∠B are equal. This is … ehrlich pest control locations miami